Two vertices of Triangle are A(6,4) and B(-2,2) If the centriod is find the third vertex of the triangle and also find the area of Triangle ABC
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Centroid of the circle is given by [(x1 + x2 + x3)/3],[(y1+y2+y3)/3]
Here (6+-2+x)/3=3
∴(x+4)/3=3
∴x+4=9
∴x=5
and (4+2+y)/3=4
∴(6+y)=12
∴Y=6
Hence the other vertex of the triangle is C(5,6)
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