Chemistry, asked by sumitdhingra3308, 1 year ago

Two vessels a and b are filled with dilute sulfur ic acid (i .E. Mi xt ur e of sul fur i c aci d and wat er ). Vessel a has t he r at i o of aci d and wat er i n 1 : 2, whi le the vessel b has the rat io of acid and water in 3 : 1. To prepare 5 l i t re mixture, di lute sulfur ic acid containing equal amount of acid and water

Answers

Answered by amitnrw

Answer:

3 liter from Vessel A

2 Liter from Vessel B

Explanation:

Two vessels a and b are filled with dilute sulfur ic acid (i .E. Mi xt ur e of sul fur i c aci d and wat er ). Vessel a has t he r at i o of aci d and wat er i n 1 : 2, whi le the vessel b has the rat io of acid and water in 3 : 1. To prepare 5 l i t re mixture, di lute sulfur ic acid containing equal amount of acid and water

Vessel A Acid : water :: 1 : 2

Let say 3x liter of Vessel A is taken

then x liter is acid & 2x liter is Water

Vessel B Acid : water :: 3 : 1

Let say 4y liter of Vessel B is taken

then 3y liter is acid & y liter is Water

3x + 4y = 5 ( total Mixture)

Acid = x + 3y

Water = 2x + y

Acid = water

=> x + 3y = 2x + y

=> 2y = x

3x + 2x = 5

=> x = 1

=> y = 1/2

Taken from Vessel A 3x = 3 litre

Taken from Vessel B 4y = 2 litre

Answered by ᎷíssGℓαмσƦσυs

Explanation:

Answer:

3 liter from Vessel A

2 Liter from Vessel B

Explanation:

Vessel A Acid : water :: 1 : 2

Let say 3x liter of Vessel A is taken

then x liter is acid & 2x liter is Water

Vessel B Acid : water :: 3 : 1

Let say 4y liter of Vessel B is taken

then 3y liter is acid & y liter is Water

3x + 4y = 5 ( total Mixture)

Acid = x + 3y

Water = 2x + y

Acid = water

=> x + 3y = 2x + y

=> 2y = x

3x + 2x = 5

=> x = 1

=> y = 1/2

Taken from Vessel A 3x = 3 litre

Taken from Vessel B 4y = 2 litre

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