Question

Two vessels A and B are filled with dilute sulfuricacid (i.e. mixture of sulfuric acid and water).Vessel A has the ratio of acid and water in1:2, while the vessel B has the ratio of acid andwater in 3: 1. To prepare 5 litre mixture, dilutesulfuric acid containing equal amount of acid andwater(a) 2 and 3 litre(6) 3 and 2 litre(c) 1 and 4 litre(d) 4 and 1 litre​

Answer 1

Answer

Let x be amount from A and (5 - x) amount from B

x / 3 + (5 - x) * 3/4 =   total acid in final mixture

2 x / 3 + (5 - x) * 1/4 = total water in final mixture

x / 3 + (5 - x) * 3/4 = 2 x / 3 + (5 - x) * 1/4

x ( 2/3 + 3/4 - 1/3 -1/4) = 15/4 - 5/4 = 10/4

x ( 8 + 9 - 4 -3) /12 = 10/4

10 x / 12 = 10/4

x = 3       so take 3 liters from A and 2 liters from B

Total acid = 1/3 * 3 + 3/4 * 2 = 2.5

Total water = 2/3 * 3 + 1/4 * 2 = 2.5