Math, asked by as4967309, 1 year ago

two vessels a and b contain mixtures of spirit and water are in ratio of 7:2 and 5:3. the ratio in which these are mixed to obtain new mixture which contains spirit and water in the ratio 5:2 is = ?

Answers

Answered by ram071987
2
spirit in 1st = 7/9
spirit in 2nd = 5/8
spirit in new mixture = 5/7
by mixture and allegations,
ratio of spirit 1
7/9 - 5/7 = (49 - 45)/63 = 4/63
ratio of spirit 2
5/7 - 5/8 = (40 - 35)/56 = 5/56
so required ratio
4/63 : 5/56
= 4/9 : 5/8
=32 : 45
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