Math, asked by yogeenit006, 7 months ago

two vessels a and b contain spirit and water in the ratio 2:3 and 4:7 respectively. their contents are mixed in the ratio 5:11. in 160 ml of this solution, how much spirit should be added to make it soluntion of spirit and water in ratio of 7:10
a)20ml,b)5ml,c) 10ml

Answers

Answered by Anonymous
0

Answer:

Solution:

Solution:Option(C) is correct

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. 

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13 

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)       /          \

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)       /          \(1/13)     :     (9/91)

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)       /          \(1/13)     :     (9/91)  7                      9

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)       /          \(1/13)     :     (9/91)  7                      9Therefore required ratio = 1/13 : 9/91 

Solution:Option(C) is correctSpirit in 1 litre mix of A = 5/7 litre.Spirit in 1 litre mix of B = 7/13 litre.Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y   X         :       Y 5/7              7/13        \          /          (8/13)       /          \(1/13)     :     (9/91)  7                      9Therefore required ratio = 1/13 : 9/91 = 7:9

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