Math, asked by prakash4696kr, 11 months ago

Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 : 6
respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in
vessel C containing spirit and water in the ratio 8:5?
(a) 3:4
(b) 4:3
(C) 9:7
(d) 7:9​

Answers

Answered by itzshrutiBasrani
2

☆Answer☆

Let the C.P. of spirit be Re. 1 litre.

Spirit in 1 litre mix. of A = 5/7 litre, C.P. of 1 litre mix.

in A = Re. 5/7

Spirit in 1 litre mix. of B = 7/13 litre, C.P. of 1 litre mix.

in B = Re. 7/13

Spirit in 1 litre mix. of C = 8/13 litre, Mean price = Re. 8/13.

 

By the rule of alligation, we have:

Cost of 1 litre mixture in A                          Cost of 1 litre mixture in B

Required ratio = 1/13 : 9/91 = 7:9.

☆Hope it Helps☆

Similar questions