Question

Two vessels A and B contains spirit and water in the ratio 5:2 and 8:3. Their contents are mixed in the ratio 7: 11. In 360 ml of this solution, how much water should be added so that the mixture contains spirit and water in the ratio 5:3?​

Answer 1

Answer:

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Step-by-step explanation:

spirit in 1st = 7/9

spirit in 2nd = 5/8

spirit in new mixture = 5/7 by mixture and allegations,

ratio of spirit 1

7/95/7 (49 - 45)/63 = 4/63

=

ratio of spirit 2

5/7-5/8 (40 - 35)/56 = 5/56 =

so required ratio

4/63 : 5/56

= 4/9 : 5/8

=32:45