Physics, asked by roshni5696, 11 months ago

Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four times that in B. The ratio of the liquid thrust at the base of A to that at the
base of B is : explain ur ans guys, do not spam..​

Answers

Answered by princektr
0

Answer:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction:

Dry friction is a force that opposes the relative lateral motion of two.

Answered by MrEccentric
0

Hey mate!

Thank you for asking this question! ❤

Answer:

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The thrust due to any liquid at the bottom of the vessel is only a function of its base area.

Since, in the given problem, both the vessels have the same base area therefore, they will have an equal thrust due to liquid.

Hence, the ratio of the thrusts is equal to 1:1...

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Hope it helps you! ヅ

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