Question

Two vessels A and B of equal capacities contain mixtures of milk and water in the ratio 4 : 1 and 3 : 1, respectively. 25% of the mixture from A is taken out and added to B. After mixing it thoroughly, 20% of the mixture is taken out from B and added back to A. The ratio of milk to water in vessel A after the second operation is

Answer 1

SOLUTION :-

FOR 'A'

let there be 5 litres of mixture, then
milk = 4 litres and water = 1 litres.

FOR 'B'

let there be 4 litres of mixture, then
milk = 3 litres and water = 1 litres.

so, in 25% of 'A' , 25/100×5 = 1.25 litres of mixing.

milk = 4/5× 1.25 = 1 litres.
water = 1/5× 1.25 = 0.25 litres.

NEW 'B'

milk = 3 + 1 = 4 litres.
water= 1 + 0.25 = 1.25 litres.

In 20% of new 'B' = 20/ 100× 5.25 = 1.05 litres.

milk = 4/5.25 × 1.05 = 0.8 litres.
water = 1.25/ 5.25× 1.05 = 0.25 litres.

WHEN ADDED TO 'A' NEW 'B'

milk= 0.8 + 4= 4.8 litres.
water= 0.25+ 1= 1.25 litres.

therefore, milk / water
= 4.8/ 1.25
= 3.84

Answer 2

Answer:

80:20 ---- A

75:25 ---- B

25% === 20:5 taken from A

95:30 ----- B

Now A ---- 60:15

Taken from B --- 19:6

79:21