Question

Two vessels contain a mixture of milk and water.the content of the mil is 60% in the first vessel and 30% in the second vessel. in what ratio must the mixtures from the first and second vessel be taken to firm a mixture containing 50% milk​

Answer 1

Answer:

Given:

Ratio of milk and water in the first vessel = 2 ∶ 3

Ratio of milk and water in the second vessel = 9 ∶ 7

Concept Used:

Mixtures and Alligations

Calculation:

Let the required ratio of mixtures 1 and 2 = x ∶ y

So, we get:

Amount of milk in the first vessel = (2/5)x

Amount of water in the first vessel = (3/5)x

Amount of milk in the second vessel = (9/16)y

Amount of water in the second vessel = (7/16)y

To make the quantities of milk and water to be equal on mixing the two mixtures, we need to have:

(2/5)x + (9/16)y = (3/5)x + (7/16)y

⇒ x/5 = y/8

⇒ x/y = 5/8

∴ The required ratio of the quantites of the two vessels to be mixed will be 5 ∶ 8

Ratio of milk and water in the first vessel = 2 ∶ 3

⇒ Ratio of milk and total content in first vessel = 2 : 5

Ratio of milk and water in the second vessel = 9 ∶ 7

⇒ Ratio of milk and total content in second vessel = 9 : 16

If ratio of milk and water is 1 : 1, then ratio of milk and total content = 1 : 2

Reported 1.1.3

⇒ Required ratio = 1/16 : 1/10 = 5 : 8

∴ Required ratio is 5 ∶ 8.

Step-by-step explanation:

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