Math, asked by mainak564, 11 months ago

two vessels contain a mixture of two liquids A and B in ratio 9 : 4 and 5 :3 in which ratio must liquid be taken from each vessel to give a mixture of liquid A and B in ratio of 2 : 1​

Answers

Answered by Delores
8

Answer:

16 : 13

Step-by-step explanation:

9+4 = 13, 5+3 = 8

13×8 = 104

104×5 = 520 (times 5 to make the calculation easier)

Vessel 1:

A:B = 360ml : 160ml

Vessel 2:

A:B = 325ml : 195ml

To get ratio 2:1 in Vessel 1, 360/2 = 180ml, we cannot add liquid, so we take 160×2 = 320ml, 40ml of Liquid A in Vessel 1 is taken out.

To get ratio 2:1 in Vessel 2, 195×2 = 390ml, we cannot add liquid, so we take 325/2 = 162.5ml, 32.5ml of Liquid B in Vessel 2 is taken out.

A:B

= 40ml:32.5ml

= 80:65

= 16:13

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