Two vessels contain milk and water in the ratio 2:3 and 7:3. Find the ratio in which the contents of the two vessels
have to be mixed so that the ratio of milk and water in the new mixture is equal.
A. 2:1
B. 1:2
C 3.2
D. 2:3
Answers
Answer:
2+7/3+3
=9/6
=3/2
=3:2
Answer:
Step-by-step explanation:
Answer=Vessel A : Vessel B:: 7:5
Ratios are 4:3 (4+3=7) and 2:3 (2+3=5). So LCM of 7, 5 is 35.
Now, for 35 liter mix.
Let M=milk,W=water
Vessel A,
M:W= 4:3 (4+3=7) means in 35 liter mix. Milk is 4*35/7=20 liter and water is 3×35/7=15 liter.
Vessel B,
M:W=2:3(2+3=5) means in 35 liter mix. Milk is 2×35/5=14 liter and water is 3×35/5=21 liter.
For Vessel C,
M:W=1:1(required)
Let ratio of Vessel A=x and Vessel B=y.
In Vessel C , both milk and water will be in equal quantity. So,
Net quantity of milk= Net quantity of water
20x+14y=15x+21y
5x=7y
x/y=7/5
So, x:y=7 :5
Vessel A : Vessel B:: 7:5
Answer check-
Vessel A, milk=20×1.4=28 liter,water=15×1.4=21 liter and net quantity=28+21=49 liter
Vessel B , milk=14 liter, water=21 liter and net quantity=35 liter
Afrer Mixing both Vessels,
Net quantity=49+35=84 liter
Milk=28+14=42 liter
Water=21+21=42 liter