Question

Two vessels containing gases A and B are interconnnected
as shown in the figure. The stropper is opened the gases
are allowed to mix homogeneously. The partial pressure
of A and B in the mixture wll be a respectively
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Answer 1

Answer:

pA + pB .. add the partial pressure of both the gases

Answer 2

Answer:

Explanation:

For moles of A

nA= PA×VA/RT

And for moles of B

nB = PB×VB/RT

For total pressure

Pt×Vt= nt×RT

Pt × (12+8)= (nA + nB) × RT

    136/RT ×RT

Pt = 136/20 atm

PA = XA × Pt

     = (nA / nt) × Pt

      4.8 atm

Similarly PB= 2 atm