two vessels seperately contain two ideal gases A and B at the same temperature. the pressure of Abeing twice that of B. under such conditions , the density of A is found to be 1.5 times the density of B. the ratio of molecular weight of A and B is
a) 3/4 b) 2 c) 1/2 d) 2/3
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Answer:
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Answer:
a 3/4
Explanation:
Pa= 1.5 Pb
Pb = 2 Pb
According to the ideal gas equation we have pressure,p =pRT/M , where M is the molecular weight of the ideal gas
such that p/p = pRT/M
therefore M = pRT/p
where R and T are constant
so,M is proportional to p/p
Ma/Mb = Pa/Pb × Pb/Pa = 1.5 ×1/2 =0.75 = 3/4
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