Two voltages are given by e1=30sin(ωt +π/6) and e2=20sin(ωt- π/6). The voltage e1 leads e2 by ?
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Answer:
mpedence Z =
I
max
V
max
Z=
5
110
=22Ω
Average power disipation is P
P=
2
V
max
I
max
cos∅
=
2
110×5
×cos(
3
π
)
P
avg
=137.5
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