Two voltmeter of resistance 15 kilo ohm and 20 kilo ohm are connected in series across 200v supply. Both meter are 0 to 300v range. Find the reading of the voltmeter.
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The voltage source and the two voltmeters are connected in series here, so then the current must be constant.
Let me find the current I first.
By Ohm’s law, I = 240 / ( 15000 + 5000 ) = 240 / 20000 = 0.012 A.
Hence again by ohm’s law,
Voltage reading across voltmeter 1 is 0.012 * 15000 = 180 v.
Voltage reading across voltmeter 2 is 0.012 * 5000 = 60 v.
Method II :-
By voltage division rule,
Voltage reading across voltmeter 1 is = ( 240 * 15000 ) / ( 20000 ) = 180 v.
Voltage reading across voltmeter 2 is = ( 240 * 5000 ) / ( 20000 ) = 60 v.
This can be verified by Kirchoff’s voltage law ( Sum of the voltage sourcing = Sum of voltage drops ) as,
240 v = 180 + 60 v =240
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