Two walls and the ceiling of a room meet at right angles at point p.A fly is in the air one metre from one wall and eight meters from another wall and 9 meters from point p.how many meters is the fly from the ceiling?
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Answer:
distance form ceiling is 4
Step-by-step explanation:
Since we are given that
distance from one wall = x = 1
distance from from other wall = y = 8
distance from point p and origin = D
Let the distance from the ceiling is z then according to distance formula
in space for the point p(x , y , z) .
D = √(x² + y² + z²)
Putting the values we get
9 =√(1² + 8² + z²)
Taking square on both sides we get
9² = (1² + 8² + z²)
⇒ 81 = 1 + 64 + z²
⇒ z² = 81 - 65 = 16
Taking under root on both sides we get
z² = ±4
So there are two possibilities for z
Therefor the point is either (1 , 8 , 4) or (1 , 8 , -4)
Thus distance from ceiling in both cases is 4.
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