Two watches are such that every hour, one loses a minute and other gains half a minute. If both watches
show the same time right now, after how long (in hours) will the difference between the times be exactly
one hour?
Answers
Answered by
3
Answer:
9:44 am
Step-by-step explanation:
The answer is option D
Speed of 1
st
clock =58min/hr
Speed of 2
nd
clock =61min/hr [Since it gains 2min in 2hrs, it should gain 1min in 1hr]
Relative velocity of 2
nd
clock wrt 1
st
=61−58=3min/hr
Relative distance travelled by the 2
nd
clock wrt 1
st
by the time both are stopped =1hr6min=66min
Time taken by the 2
nd
clock wrt 1
st
to cover 66min=66/3=22hours
In those 22 hours, mins covered by the 1
st
clock =22×58=1276
The actual mins elapsed in those 22hours=22×60=1320
∴ Number of mins the 1
st
clcok is behind the correct time=1320−1276=44mins
⇒ If the time on the 1
st
clock is 9am, then the correct time is 9:44am
Answered by
1
Answer:
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