Question

Two water pipes can fill a tank in 2hours.the tap of larger diameter takes 3 hours less than the smaller ones

Answer 1

Answer:

hey mate

Step-by-step explanation:

Solution :-

Let the tap of larger diameter takes time to fill the tank = x hrs

Then, the tap of smaller diameter takes time to fill the tank = (x + 2) hrs

In 1 hour, tap of larger diameter will fill = 1/x part of tank 

In 1 hour, tap of smaller diameter will = (1/x + 2) part of tank

Together, both the taps take time to fill the tank = 2 11/12 hrs

In 1 hour, both the taps will fill = 12/35 part of tank

∴ 1/x + 1/(x + 2) = 12/35

Taking the LCM and then solving it.

⇒ (x + 2 + 2)/(x + 2)(x) = 12/35

⇒ (2x + 2)/(x² + 2x) = 12/35

⇒ 12x² + 24x = 70x + 70 

⇒ 12x² + 24x - 70x - 70 = 0

⇒ (12x² - 46x - 70 = 0) ÷ 2

⇒ 6x² - 23x - 35 = 0

⇒ 6x² - 30x + 7x - 35 = 0

⇒ 6x(x - 5) + 7(x - 5) = 0

⇒ (6x + 7) = 0 or (x - 5) = 0

⇒ x = - 7/6 or x = 5

x = - 6/7 is not possible because time cannot be negative. So, the correct value of x is 5.

So, time taken by tap of larger diameter is 5 hours and time taken by tap of smaller diameter is 5 + 2 = 7 hours separately

Answer 2

Answer:

Form sentence based on ur question ..

X = - 6/7 , the value cannot be negative..

so kept as 5

5+ 2 = 7 ok