Question

Two water pipes P and Q having
40-2 m and 4 x 10-2 m respectively are joined
in series with the main supply line of water. The
elocity of water flowing in pipe P is​

Answer 1

The velocity of water flowing in pipe P is​  vp = vq 4

Explanation:

Correct statement:

Two water pipes p and q having diameters 2 x  10^ -2 2× 10  −2  m and 4 x 10^-2 m, respectively, are joined in series with the main supply line of water. The velocity of water flowing in pipe P is

Given:

dp = 2 x 10^-2 m

rp = 10^-2 m

dq = 4 x 10^-2 m

rq = 2 x 10^-2 m

The velocity of water flowing through the pipe is inversely proportional to the cross-sectional area of tube, hence we can write .

Vp / Vq = aq / ap

where vp , vq   are velocities of water through both pipes and ap , aq  are the cross-sectional area of tubes.

ap = π ( rp)^2

aq = π (rq)^2

vp / vq = π (rq)^2 / π ( rp)^2

vp / vq = ( 2 x 10^-2)^2 / ( 10^-2)^2

vp / vq = 4

vp = vq 4

Thus the velocity of water flowing in pipe P is​  vp = vq 4

 

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