Question

two
water pipes P and Q having diameter
10-2 m and 4 x 10-2 m respectively are joined
ceries with the main supply line of water. The
velocity of water flowing in pipe Pis
(1) Four times that of Q (2) Two times that of Q
(3) 1 times that of Q (4) á times that of Q​

Answer 1

Answer:

Diameter of pipe P = 2 × 10-2 m Diameter of Pipe Q = 4 × 10-2 m Acc. to the equation of continuity a1 v1 =a2 v2 ap vp = aq vq →A aQ, aP = Cross – section area of pipe P and Q vP, vQ = Velocity of liquid at pipe P and Q i.e. Velocity of water in pipe P is four times the velocity of water in pipe

Answer 2

The velocity of water of pipe P is four times the velocity of water of pipe Q.

(1) is correct option.

Explanation:

Given that,

Diameter of P $D_{p}= 2\times10^{-2}\ m$

Diameter of Q$D_{q}=4\times10^{-2}\ m$

We need to calculate the velocity

Using Bernoulli theorem

$A_{1}v_{1}=A_{2}v_{2}$

Put the value into the formula

$\dfrac{\pi\times(2\times10^{-2})^2}{4}\times v_{1}=\dfrac{\pi\times(4\times10^{-2})^2}{4}\times v_{2}$

$\dfrac{v_{1}}{v_{2}}=\dfrac{4}{1}$

$v_{1}=4v_{2}$

Hence, The velocity of water of pipe P is four times the velocity of water of pipe Q.

Learn more :

Topic : velocity

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