Two Water Tanks can fill a tank in 1 7/8 hrs. The tap with longer diameter takes 2 hrs less than the tap with smaller one to fill the tank separately. Find the time in which each tank can fill the tank separately.
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Answered by
4
Answer:
5hr , 3hr
Step-by-step explanation:
Let the time taken by smaller dia be x
So, the time taken by bigger dia tap = x-2
Time work efficiency
x x-2
x(x-2)
x-2 x
Total efficiency = 2x-2
Here, x(x-2) is total work
So, x(x-2)
--------- = 15/8 (given)
2x-2
Or, 4x^2 - 8x = 15x -15
4x^2 - 23x + 15 = 0
x = 23 (+/-)√(529-240)
-----------------------------
8
x = 23 (+/-)17
------------------
8
x = 40/8 = 5 hours
or x = 6/8 (impossible)
so one takes , 5 and another 3
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