Math, asked by Defsoul, 1 year ago

Two Water Tanks can fill a tank in 1 7/8 hrs. The tap with longer diameter takes 2 hrs less than the tap with smaller one to fill the tank separately. Find the time in which each tank can fill the tank separately.

Answers

Answered by streetburner
4

Answer:

5hr , 3hr

Step-by-step explanation:

Let the time taken by smaller dia be x

So, the time taken by bigger dia tap = x-2

Time work efficiency

x x-2

x(x-2)

x-2 x

Total efficiency = 2x-2

Here, x(x-2) is total work

So, x(x-2)

--------- = 15/8 (given)

2x-2

Or, 4x^2 - 8x = 15x -15

4x^2 - 23x + 15 = 0

x = 23 (+/-)√(529-240)

-----------------------------

8

x = 23 (+/-)17

------------------

8

x = 40/8 = 5 hours

or x = 6/8 (impossible)

so one takes , 5 and another 3

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