Question

two water taps can together fill a tank in 6 hours the tap of larger diameter takes 9 hour less than the smaller one to fill the tank separately find the time in each tap separately ​

Answer 1

Step-by-step explanation:

Let the time taken by larger diameter tab be (x-9)

and of smaller diameter be x

Now

1/x + 1/x-9=1/6

x-9+x/(x-9)x=1/6

6(2x-9)=x(x-9)

12x-54=x^2-9x

x^2-21x+54

x^2- 18x- 3x+54

x(x-18) - 3(x-18)

x=18 or x=3

So x =18

The time taken by tap of larger diameter is 9 hrs and of smaller diameter is 18 hrs