Question

‘Two water taps together can fill a tank 9 and 3/8 hours. The tap of larger diameter takes 10 hour less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank

Answer 1

Answer:

hope this is useful for you

Answer 2

Answer:

Step-by-step explanation:

Let smaller tap fill the tank in x hrs

Therefore,bigger tap fills in (x-10) hrs.

Both fill in = 75÷8 hrs

Part filled by smaller tap in 1 hr = 1÷x

Part filled by bigger tap in 1 hr =

1÷(x-10)

Part filled by both in 1 hr = 8÷75

Therefore

(1÷x) + {1÷(x-10)} = 8÷75

[(x-10) + x]÷ x(x-10) = 8÷75

[2x-10]÷x(x-10) = 8÷75

75(2x-10) = 8[x(x-10)]

159x-750 = 8x²-80x

8x²-230x+750 =0

4x²-115x+375 = 0

4x²-100x-15x+375= 0

(x-25)(4x-15) = 0

Therefore x = 25 or 15÷4

But x ≠ 15÷4 because x-10 < 0

So x = 25

Therefore

Time taken by smaller tap = 25 hrs

And time taken by bigger tap = 15 hrs

Hope it helps you

Im only 14 so please like my answer and mark me brainliest