Question

two water taps together can fill a tank in 15/8hours . the tap with longer diameter takes
2hours less then the tap with smaller diameter to fill the tank separately .

find the in which each tap can fill the tank separately

Answer 1

Answer:

here is your answer!

Explanation:

Let there be two taps A and B and let A be the tap with longer diameter than tap B then.

tap A takes 2 hours less than tap B if tap B is taking X hours the. Tap A would take (X-2) hours

Now,

1/x + 1/(x-2) = 8/15

= x-2 + x / x^2-2x =8/15

= (2x-2 )15 = 8(x²-2x)

= 30x - 30 = 8x² - 16x

=8x²-16x-30x+30= 0

=8x² -46x +30 = 0

divide the eq by 2 we get

=4x²-23x+15=0

=(4x²-20x)-(3x+15)=0

=4x(x-5)-3(x-5)=0

=(4x-3)(x-5)=0

x=3/4 or x=5

if x=5

then x-2=3

therefore time taken by tap A=xhours=5hours and time taken by tap B=x-2 hours =5-2=3 hours.

hope it helps

please mark as brainliest

happy holi

all the best!