Question

two water taps together can fill a tank in 3 hours 45 minutes. the tap with larger diameter takes 10 hours less than the smaller one to fill the tank separately. calculate the time taken by the larger tap to fill the tank alone

Answer 1

Answer:

1 hours 55mins

Step-by-step explanation:

Let the time taken by smaller diameter pipe be x hours. This brings us to situation that time taken by larger diameter be x-10 hours. So to frame the equation of amount of water filled by both taps together as

1/x + 1/(x-10) = 1/3.45

as 3 hrs 45 mins is the total time taken by both which is equal to 3.45 hours

This equation deduces itself to

6.9x-34.5= x²-10x

x²-3.1x+34.5=0

Larger diameter tap takes =1.55 hours