Two water taps together can fill a tank in 4 2/8 hours.The tap of larger diameter takes 20 hours less than the smaller one to fill the tanks seperately.Find the time in which each tap can seperately fill the tank.
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Time taken by tap with diameter=x
Time taken by tap with larger diameter =x-20
part of tank filled by smaller tap=1/x
part of tank filled by larger tap=1/x-20
part together the fill =1/x+1/x-20
2x-20/x^2+20x=4/17
34x-340=4x^2-80x
4x^2-80x-34x+340=0
this is the equation
factorise to get answer
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