Question

two water taps together can fill a tank in 6 hours the top of larger diameter takes 9 hours less than the smaller one to fill the tank separately find the time in which each two up can separately fill the tank please tell fast I don't have time​

Answer 1

Answer:

9 hours will be your correct answer !

Step-by-step explanation:

Let the time taken by the smaller tap to fill the tank = x hours  

time taken by larger tap = x - 9

In 1 hour, the smaller tap will fill 1/x of tank

In 1 hour, the larger tap will fill 1/(x-9) of tank.

In 1 hour both the tank will the tank = ⅙

In 1 hour both the tank will fill the ta⅙ = (x-9)+ (x)/(x) (x-9)

⅙ = 2x-9/x²-9x

6(2x-9) = x²-9x

12x-54= x²-9x

x²- 9x-22x +54= 0

x²- 21x+54= 0

x²-18x-3x +54=0

x(x-18)-3(x-18)=0

(x-18) (x-3)=0  

x= 18, x=3

We take x= 18  

Smaller tap(x)= 18 h

Larger tap (x-9)=18-9= 9h

Hence, the time taken by the smaller tap to fill the tank = 18 hrs & the time taken by the larger tap to fill the tank = 9 hnk= 1/x + 1/x-9