two water taps together can fill a tank in 9 3/8 hours the tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately find the time in which each step can separately fill the tank o
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Answer:
Question 1.
“Workers of my homeland! I have faith in Chile and its future…… It will be a moral lesson to castigate felony, cowardice, and treason.” Who said this?
(a) General Augusto Pinochet
(b) General Alberto Bachelet
(c) Salvador Allende
(d) Michelle Bachelet
Answer:
Let the tap with smaller diameter fills the tank alone in x hours
Let the tap with larger diameter fills the tank alone in (x – 10) hours.
In 1 hour, the tap with a smaller diameter can fill 1/x part of the tank.
In 1 hour, the tap with larger diameter can fill 1/(x – 10) part of the tank.
The tank is filled up in 75/8 hours.
Thus, in 1 hour the taps fill 8/75 part of the tank.
1/x + 1/(x-10) = 8/75
(x-10) + x / x(x-10) = 8/75
2x – 10/x(x-10) = 8/75
75 (2x-10) = 8(x2-10x) by cross multiplication
150x – 750 = 8x2 – 80x
8x2 − 230x + 750 = 0
4x2−115x + 375 = 0
4x2 − 100x −15x + 375 = 0
4x(x−25)−15(x−25) = 0
(4x−15)(x−25) = 0
4x−15 = 0 or x – 25 = 0
x = 15/4 or x = 25
Case 1: When x = 15/4
Then x – 10 = 15/4 – 10
⇒ 15-40/4
⇒ -25/4
Time can never be negative so x = 15/4 is not possible.
Case 2: When x = 25 then
x – 10 = 25 – 10 = 15
∴ The tap of smaller diameter can separately fill the tank in 25 hours and the time taken by the larger tap to fill the tank = ( 25 – 10 ) = 15 hours.
Step-by-step explanation:
it is a right answer, aap Apne idia se ese aur achhe se likh sakte ho