Question

Two water taps together can fill a tank in 9 3/8.The tap of larger diameter takes 10
hours less than the smaller one to fill the tank separately. Find the time in which each tap
can separately fill the tank. in quadratic equation chapter​. in 10 th class

Answer 1

Step-by-step explanation:

Let tap of smaller diameter can separately fill the tank in x hours

let the tap of larger diameter can separately fill the tank in (x-10) hours

Portion of tank filled by the tap of smaller diameter in 1 hour = 1/x .

Portion of tank filled by the tap of larger diameter in 1 hour=1/(x-10).

Portion of tank filled by both the taps in 1 hour

= 1/x+1/(x-10).

ACCORDING TO QUESTION.

(1/x+1/x-10)×75/8 = 1

x-10+x/x(x-10)=8/75

75(2x-10)=8x^2-80x

8x^2-80x-150x+750=0

8x^2-230x+750=0

4x^2-100x-15x+375=0

4x(x-25) - 15(x-25)=0

x=15/4 and x=25

If x=15/4

15/4-10=15-40= -25/4

Not possible because time can't be negative

therefore,x=25

Ans. Tap of smaller diameter can separately fill tank in 25 hours.

Tap of larger diameter can seperately fill tank in (25-10)= 15 hours.

Answer 2

Step-by-step explanation:

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