two water taps together can fill a tank in annual day. How much tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately find the time in which each can separately fill the tank
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let the time taken to fill the full tank by tap of smaller diameter alone =x then by larger diameter = x-10
now in 1 hr = 1/x-10
now,
1/x-10+ 1/x = 1/ 24
now by solving this equation you can find the answer
now in 1 hr = 1/x-10
now,
1/x-10+ 1/x = 1/ 24
now by solving this equation you can find the answer
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