Math, asked by khushi4063, 11 months ago

two water taps together can fill a tank in in 75 upon 8 hours. the tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. find the time in which each tap can separately fill the tank.​

Answers

Answered by muhammedshez7
2

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Attachments:
Answered by ItzmysticalAashna
12

Answer:

Answer:

\huge\underline\mathrm\green{Answer-}

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Tap of smaller diameter can fill the tank in 25 hours separately.

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\huge\underline\mathrm\red{Explanation-}

Explanation−

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Let tap of smaller diameter can fill the tank in x hours.

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So, tap of larger diameter can fill the tank in (x - 10) hours ( as mention in the question )

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In 1 hour, tap of smaller diameter can fill tank in \dfrac{1}{x}

x

1

hours.

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Similarly, In 1 hour, tap of larger diameter can fill tank in \dfrac{1}{x-10}

x−10

1

hours.

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It is given that, both taps can fill the tank in \dfrac{75}{8}

8

75

hours. So, in hour, both taps can fill tank in \dfrac{8}{75}

75

8

hours.

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\therefore∴ \large{\boxed{\rm{\dfrac{1}{x}\:+\:\dfrac{1}{x-10}\:=\:\dfrac{8}{75}}}}

x

1

+

x−10

1

=

75

8

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★ Taking LCM,

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:\implies⟹ \rm{\dfrac{x-10+x}{x(x-10)}\:=\:\dfrac{8}{75}}

x(x−10)

x−10+x

=

75

8

:\implies⟹ \rm{\dfrac{2x-10}{x^2-10x}\:=\:\dfrac{8}{75}}

x

2

−10x

2x−10

=

75

8

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★ By cross multiplying,

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:\implies⟹ \rm{75(2x-10)\:=\:8(x^2-10)}75(2x−10)=8(x </p><p>2</p><p> −10)

implies⟹ \rm{150x-750=8x^2-80} 150x−750=8x

2

−80

</p><p>:\implies⟹ \rm{8x^2-230x+750=0}

2

−230x+750=0

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★ Taking 2 as common

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: \implies⟹ \rm{4x^2-115x+375=0}4x

2

−115x+375=0

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★ Solving the Quadratic equation, by splitting middle term.

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: \implies⟹ \rm{4x^2-100x-15x+375=0}4x

2

−100x−15x+375=0

:\implies⟹ \rm{4x(x-25)-15(x-25)=0}4x(x−25)−15(x−25)=0

:\implies⟹ \rm{(4x-15)(x-25)=0}(4x−15)(x−25)=0

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We get,

\large{\boxed{\rm{\pink{x=\dfrac{15}{4}\:and\:25}}}}

x=

4

15

and25

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\bold{x=\dfrac{15}{4}}

4

15

,

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[/tex]:\implies⟹ \rm{x-10\:=\:\dfrac{15}{4}\:-\:10}x−10=[/tex]

4

15

−10

:\implies⟹ \rm{x-10=\dfrac{-25}{4}} x−10=

4

−25

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Since time can't be negative, so we reject this value.

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\therefore∴ \huge{\boxed{\rm{\blue{x=25}}}}

x=25

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Therefore, tap of smaller diameter can fill the tank in 25 hours separately.

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