two water taps together fill a tank in 75/9 hours. the tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. find the time in which each tap can separately fill the tank. represent this as an equation. what is the degree of that equation?
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the time to fill tank(together)=75/9 hr
if the small tap wants x+10 hr
then big tap wants x hr
amount of water that fill in one hr by small tap=
"by big tap=
"together=
[tex] \frac{1}{x} + \frac{1}{x+10} = \frac{9}{75} \\ \\ \frac{x+10+x}{ x^{2} +10x} =\frac{9}{75} \\ \\ (2x+10)75=(x^{2} +10x})9 \\ \\ 150x+750= 9x^{2} +90x \\ \\ divide ---by --3 \\ \\ 50x+25=3x^{2} +30x \\ 3x^{2} +30x-50x-25=0 \\ \\ 3 x^{2} -20x-25=0 a=3,b=-20,c=-25[/tex]
this is a second degree equation
if the small tap wants x+10 hr
then big tap wants x hr
amount of water that fill in one hr by small tap=
"by big tap=
"together=
[tex] \frac{1}{x} + \frac{1}{x+10} = \frac{9}{75} \\ \\ \frac{x+10+x}{ x^{2} +10x} =\frac{9}{75} \\ \\ (2x+10)75=(x^{2} +10x})9 \\ \\ 150x+750= 9x^{2} +90x \\ \\ divide ---by --3 \\ \\ 50x+25=3x^{2} +30x \\ 3x^{2} +30x-50x-25=0 \\ \\ 3 x^{2} -20x-25=0 a=3,b=-20,c=-25[/tex]
this is a second degree equation
Revolution:
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