Physics, asked by kamal096, 11 months ago

Two wavelengths of sodium light 590 nm and 596 nm are used in turn to study the diffraction taking place at a single slit of aperture 2×10
−6
m. The distance between the slit and the screen is 1.5 m. Calculate the separation between the positions of first maxima of the diffraction pattern obtained in the two cases.

Answers

Answered by Anonymous
2

Answer:

Explanation:

For first maximum,

y  

1

​  

=  

a

λD

​  

 

For 590 nm,

y  

1,590

​  

=  

2×10  

−6

 

590×10  

−9

×1.5

​  

 

y  

1,590

​  

=0.4425m

For 596 nm,

y  

1,596

​  

=  

2×10  

−6

 

596×10  

−9

×1.5

​  

 

y  

1,596

​  

=0.447m

Separation is

y  

1,596

​  

−y  

1,590

​  

=0.0045m

Answered by suraj62111
6

USE FOLLOWING STEP TO SOLVE IT...

Explanation:

SELECT TO BRAINLIST ANSWER.....

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