Question

Two wavelengths of sodium light 590 nm and 596 nm are used in turn to study the diffraction taking place at a single slit of aperture 2×10
−6
m. The distance between the slit and the screen is 1.5 m. Calculate the separation between the positions of first maxima of the diffraction pattern obtained in the two cases.

Answer 1

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Wavelength of first sodium light straight lambda subscript 1 = 590 nm

Wavelength of second sodium line, straight lambda subscript 2 = 596 nm

Aperture of single slit, d = 2 × 10^-6 m

Distance between the slit and the screen , D = 1.5 m

Separation between the first secondary maximum in the two cases is

The solution is in the attachment.

Answer 2

Explanation:

Wavelength of first sodium light straight lambda subscript 1 = 590 nm

Wavelength of second sodium line, straight lambda subscript 2 = 596 nm

Aperture of single slit, d = 2 × 10^-6 m

Distance between the slit and the screen , D = 1.5 m

Separation between the first secondary maximum in the two cases is

The solution is in the attachment.