Question

Two waves are represented by the equations
y₁ = a sin (⍵t + kx + 0.57) m and y₂ = a cos (⍵t + kx) m, where
x is in meter and t in sec. The phase difference between
them is
(a) 1.0 radian (b) 1.25 radian
(c) 1.57 radian (d) 0.57 radian

Answer 1

Explanation:

i think option c is the answer

Answer 2

Explanation:

first write both equations in terms of sin

$y 1= a \: sin \ (\omega \: t + kx + 0.57) \\ y2 = a \sin (\omega \: t \: + kx + \ \: \frac{\pi}{2} )$

$\delta \: \phi \: = \phi2 - \phi1$

when we are converting cos equation into sin we must add

$\frac{\pi}{2}$

phase difference is

The answer is option C