Two waves are represented by y = a sin (wt + 1/4
and y2 = a cos wt. What will be their resultan
amplitude at the point of interference?
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Explanation:
Two waves are represented by y1=Acoswt and y2= Asin (wt-π/6) superimposed on each other. What is the amplitude of the resultant wave?
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Vinod Gohel
Answered 3 years ago
y1=Acos wt=Asin(wt+pi/2)
y2=Asin(wt-pi/6).
To obtain y1+y2 ,we represent y1 and y2 as phasors. These phasors ,at time t=0 are represented in figure. If R is the sum,then from phasor diagrame,
R^2=A^2+A^2+2A^2cos 120degree. Therefore ,
R^2=2A^2–2A^2x1/2=A^2. Then,
R=A.
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