Question

two waves of amplitude a and 2A are made to interfere, the ratio of intensity at maxima and minima will be:

Answer 1

ratio of interference of two waves having amplitude of A & 2A respectively will be 9:1.

Imax./Imin. = (A1+A2)^2/(A1-A2)^2
Imax./Imin. = (A+2A)^2/(A-2A)^2
Imax./Imin. = 9A^2/A^2
Imax./Imin. = 9/1

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Answer 2

Given:

Amplitude of wave 1 =A

Amplitude of wave 2 = 2A

To Find: The ratio of maximum intensity to minimum intensity

$\frac{I_{max}}{I_{min}}=?$

Formula Used:

$I \propto A^2$

Intensity is proportional to the amplitude.

Calculations:

$\frac{I_{max}}{I_{min}}=\frac{(2A+A)^2}{(2A-A)^2}\\\frac{I_{max}}{I_{min}}=\frac{9}{1}$

Thus, the ratio of intensity at maxima and minima is 9:1

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