two waves of amplitude a and 2A are made to interfere, the ratio of intensity at maxima and minima will be:
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ratio of interference of two waves having amplitude of A & 2A respectively will be 9:1.
Imax./Imin. = (A1+A2)^2/(A1-A2)^2
Imax./Imin. = (A+2A)^2/(A-2A)^2
Imax./Imin. = 9A^2/A^2
Imax./Imin. = 9/1
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Imax./Imin. = (A1+A2)^2/(A1-A2)^2
Imax./Imin. = (A+2A)^2/(A-2A)^2
Imax./Imin. = 9A^2/A^2
Imax./Imin. = 9/1
if it seems to be helpful mark my answer as brainliest.
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Given:
Amplitude of wave 1 =A
Amplitude of wave 2 = 2A
To Find: The ratio of maximum intensity to minimum intensity
Formula Used:
Intensity is proportional to the amplitude.
Calculations:
Thus, the ratio of intensity at maxima and minima is 9:1
Learn more about: Interference of waves
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