Question

Two waves of wavelengths 2m and 2.02m moving with the same velocity superpose to produce 2 beats/s.The velocity of the wave is

Answer 1

Hey mate,

● Answer- 404 m/s

● Explaination-
# Given-
λ1 = 2 m
λ2 = 2.02 m
∆f = 2 Hz

# Solution-
Beat frequency is given by-
∆f = f1 - f2
∆f = v/λ1 - v/λ2
∆f = v (1/λ1 - 1/λ2)
2 = v (1/2 - 1/2.02)
2 = v (0.02/4.04)
v = 4.04 × 2 / 0.02
v = 404 m/s

Common velocity of waves is 404 m/s.

Hope this helps you...