Question

Two waves of wavelengths 99 cm and 100 cm both travelling
with velocity 396 m/s are made to interfere. The number of
beats produced by them per second is
(a) 1 (b) 2
(c) 4 (d) 8

Answer 1

Answer:

Given : λ

1

=99 cm=0.99 m and λ

2

=100 cm=1 m

Velocity of wave v=396 m/s

Frequency of first wave f

1

=

λ

1

v

=

0.99

396

Frequency of second wave f

2

=

λ

2

v

=

1

396

Thus number of beat produced per second b=f

1

−f

2

=396[

0.99

1

−

1

1

]

∴ c=4

Answer 2

Answer:

(c) 4

Explanation:

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