Question

Two windmills of height 50 CM and 40√3 m arein either side of the field. A person observes the top of the windmill from a point in between them. The angle of elevation was found to be 45° and 30°. Find the distance between the windmills .
with the picture representing the angle of elevation ,height ​

Answer 1

Answer:

Read the problem carefully, convert the data into meaningful diagram.

Let AB be a tower of height =50 m

CD be another tower of height =40 m

The observe is at 'P' and angle of elevation ∠APB=∠CPD=45

o

Distance between BD=BP+PD

In △ABP,tanθ=

BP

AB

Therefore, tan45

o

=

BP

50

⇒1=

BP

50

.....(∵tan45

o

=1)

⇒BP=50 m

In △CPD,

tanθ=

PD

CD

⇒tan45

o

=

PD

40

....(∵tan45

o

=1)

⇒1=

PD

40

⇒PD=40 m

Thus BD=BP+PD=50+40=90 m

Therefore, the distance between the windmills on either side of field is 90 m.

Answer 2

Step-by-step explanation:

hope this answer will help u