Question

two wire a and b are stretched by same force.if for a and b ya:yb=1:2,ra:rb=3:. and ia:ib=4:1,then ratio of theirextension will be

Answer 1

Explanation:

Given two wire a and b are stretched by same force. if for a and b ya:yb=1:2,ra:rb=3:1 and La:Lb=4:1,then ratio of their extension will be

• So we have Young’s modulus,
•                   y = F / a x ΔL x L
•              So ΔL = F x L / a x Y
• Also Area is directly proportional to radius.
•               a α r^2
• Now ΔLa / Δ Lb = Fa x La / aa x ya x ab x yb / Fb x Lb
• Force gets nullified. So we get
•                           = La / Lb x yb / ya x (rb / ra)^2
•       Substituting the given ratios we get
•                             = 4/1 x 2/1 x (1/3)^2
•                              = 4 x 2 x 1/9
•                             = 8/9
• So the ratio of their extension ΔLa / ΔLb = 8/9 or 8:9  

Reference link will be

https://brainly.in/question/16170214