Question

two wire a and b of equal mass and same materials are taken the diameter of the wire a is half of the diameter b if the resistance of wire is 24 ohm what will be the resistance of b​

Answer 1

Answer:

1/4 of the resistance of wire a ,i.e, 6

Explanation:

let rho be=P. (material is same)

length be =l

diameter of wire b=2d

radius be =2r

diameter of wire a=d

radius be=r

R of wire a=(Pl)/A

=(Pl)/πr²

R if wire b=(Pl)/A'

=(Pl)/π(2r)²

=(Pl)/4πr²

=(1/4)*(Pl)/πr²

therefore R of wire b= (1/4) R of wire a

=(1/4)*24

=6ohm

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