Question

Two wires A and B are of equal length,different area of cross section and made up of same metal
a. Name the property which is same for both the wires .
b. Name the property which is different from both the wires .
c. If the resistance of wire is 4 times the resistance of wire B, calculate the ratio of the area of cross section of the wire .

guys plz answer me ........

Answer 1

Heya!!! ✌️✌️

_____________^_^

Here is your answer dear........

Two wires A and B are of equal length, different cross – sectional areas and made of the same metal (A) Name the property which is same for both the wires
Answer: As the resistivity is independent of cross – sectional areas resistivity is same for both the wires
(B) Name the property which is different for both the wires
Answer: As the resistance of the material depends on both the length and cross sectional area of the wire resistance changes.
(C) If the resistance of the wire A is 4 times the resistance of wire B, Calculate the ratio of the radii of the wires.
Answer:
As the resistance is inversely proportional to the square of the radius of the conductor,
Ratio of the radii of the wires is RB : RA = 2:1

I HOPE THIS WILL HELP YOU OUT.....

HAVE A GREAT DAY DEAR.....

#Bhavana ☺️

Answer 2

Given : resistivity , length of two wires are equal and area of the cross section is different

Explanation:

since the resistivity , length of two wires are equal

and the area of the cross section is different

we know that

$R =\frac{ \rho L}{A}$

where R is the resistance , P is the resistivity , L is the length and A is the area of the cross section

(a) Name the property which is same for both the wires

Resistivity is  same for both the wires

(b) Name the property which is different from both the wires

Resistance  is different from both the wires  as the area of cross section is different

(c) If the resistance of wire is 4 times the resistance of wire B, calculate the ratio of the area of cross section of the wire

$R_A = 4 R_B\\\\\frac{\rho_AL_A}{A_A}= 4\times \frac{\rho_BL_B}{A_B} \\\\since\\\\\rho_A= \rho_B\\\\L_A= L_B\\\\thus\\\\\frac{A_A}{A_B}=\frac{1}{4}$

Thus the ratio is 1:4