Question

two wires A and B equal masses and of same matel are taken. the diameter of the wire A is half the diameter of the wire B if the resistance of the wire A be 24 ohm calculate the resistance of the wire B ​

Answer 1

Answer:

Resistivity is cool.

R = 6 please go through the explanation

Explanation:

For A:

         Area = (pi*d^2)/4

         [let diameter for wire A be d and since "the diameter of wire A is half of            

         that of wire B" we'll let the diameter for wire B = 2d]

 

        Cross-Sectional-Area for wire A: $\pi$d^2/4

       

        R = ρL/A

        24 = ρL/ ($\pi$d^2/4)

        24 = ρL * 4/$\pi$d^2

        24 = 4ρL/ $\pi$d^2

        RB: [resistance of wire B]

     

        R = ρL/A

        R = ρL/ $\pi$2d/2^2

        R = ρL/ $\pi$d^2

   

        24/R  =  4ρL/ $\pi$d^2 *

        24/R  =  (4ρL$\pi$d^2)  /  (ρL

        24/R  =  4 / 1  [<-- you get this fraction after simplifying]

        24 = 4R

        4R = 24

        R = 6

       let's gooooo we're done !

There's always a chance for minor errors so forgive me if there's one, and try to correct it if found.