Physics, asked by sanayakhan2803, 9 months ago

Two wires A and B, having identical geometrical construction, are stretched from their natural length by small but equal amount. The Young modules of the wires are YA and YB whereas the densities are rhoA and rhoB. It is given that YA > YB and rhoA>rhoB. A transverse signal started at one end takes a time t1 to reach the other end for A and t2 for B.
(a) t1 < t2
(b) t1 = t2
(c) t1 > t2
(d) the information is insufficient to find the relation between t1 and t2.

Answers

Answered by bhuvna789456
1

The relation between t1 and t2 cannot be discovered.

Explanation:

We know that Y_{a}&gt;Y_{\beta}, for equal strain tension \mathrm{T}_{\mathrm{a}}&gt;\mathrm{T}_{\mathrm{\beta}}. Since \rho_{\mathrm{a}}&gt;\rho_{\beta}, \mu_{\mathrm{a}}&gt;\mu_{\beta}. Nowv_{a}=\left(T_{a} / \mu_{a}\right) and  \vee_{\beta}=\left(T_{\beta} /\left(\mu_{\beta}\right)\right)

\left(v_{a}\right) / v_{\beta}=\left.\left(T_{\beta} /\left(\mu_{\beta}\right)\right) *\left(\left(\mu_{\beta}\right) /\left(\mu_{a}\right)\right)\right\}  

The ratio \mathrm{T}_{-} \mathrm{a} / \mathrm{T}_{\beta}&gt;1 \text { but }\left(\mu_{\beta}\right) /\left(\mu_{\mathrm{a}}\right)&lt;1

So, to ask whether \mathrm{va}&gt;\mathrm{v} \beta or not, we need to know the exact proportions of \mathrm{T} \mathrm{a} / \mathrm{T}_{\beta} and \left(\mu_{\beta}\right) /\left(\mu_{\mathrm{a}}\right) Which is not mentioned here. The relation between t1 and t2 cannot, be discovered.

Answered by bestwriters
0

(d) The information is insufficient to find the relation between t₁ and t₂.

Explanation:

From question, after stretching, the young's modulus is given as:

Y_a > Y_b

Thus, the strain tension is given as:

T_a > T_b

From question, after stretching, the density is given as:

ρ_a > ρ_b

Thus,

μ_a > μ_b

Now, volume of wire 'a' is given as:

\mathrm{v}_{\mathrm{a}}=\sqrt{\left(\mathrm{T}_{\mathrm{a}} / \mu_a\right)} ⇒ (equation 1)

Now, volume of wire 'b' is given as:

\mathrm{v}_{\mathrm{b}}=\sqrt{\left(\mathrm{T}_{\mathrm{b}} / \mu_b\right)} ⇒ (equation 2)

On dividing equation 1 by equation 2, we get,

\frac{v_a}{v_b}=\sqrt{\frac{T_a}{T_b}\times \frac{\mu_b}{\mu_a}}

Now, the ratio of T_a/T_b > 1 and the ratio of μ_b_a < 1.

Since, we don't the value of ratio of T_a/T_b and μ_b_a. Thus, we are unable to find vₐ and v_b.

Thus, relationship between t₁ and t₂ cannot be found.

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