Question

Two wires A and B of equal mass and the same metal are taken. The diameter of the wire A is half the diameter of wire B. If the resistance of wire A is 24 Ω, calculate the resistance of the wire B. STEP BY STEP

Answer 1

Answer:

the resistance of wire B is 6ohm

Explanation:

Ra= pl / π(D/4)*2

Rb=pl/ π(D/2)*2

Ra/Rb= D*2/4× 16/D*2

Rb= Ra/4=24/4=6ohm

Answer 2

Answer:

Explanation:

The formula for resistance is  

As both A and B wires are made up of same material with same mass, the resistivity will be constant. So

And  

Thus the resistance ratio will be

As it is given in question that diameter of A is half of the diameter of B, the cross section area will be

Thus,

As

Thus, the resistance of wire B is 6Ω.