Two wires A and B of same material are connected in parallel.Wire A has length'l' & radius'r' & wire B has length'2l' &radius'2r'.Compute the ratio of the total resistance of parallel combination and the resistance of wire A
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since they have same material so resistivity will be same
R(A)=rl/a =rl/(pi)(r^2)
R(B)=2rl/(pi)(2r)^2 =rl/2(pi)(r^2)
therefore if
R(A)=R
R(B)=R/2
now taking parallel combination
R(p)=(R.R/2)/(R+R/2)
R(P)=R/3
now
R(P)/R(A)=R/(R/3)
THEREFORE THE ANSWER IS 3:1
R(A)=rl/a =rl/(pi)(r^2)
R(B)=2rl/(pi)(2r)^2 =rl/2(pi)(r^2)
therefore if
R(A)=R
R(B)=R/2
now taking parallel combination
R(p)=(R.R/2)/(R+R/2)
R(P)=R/3
now
R(P)/R(A)=R/(R/3)
THEREFORE THE ANSWER IS 3:1
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