Two wires A and B of the same material and having same length, have their cross sectional areas in the
ratio 1: 6. What would be the ratio of heat produced in these wires when same voltage is applied across
each?
Answers
Answered by
4
Answer:
6:1
Explanation:
R=ρl/A
Let Resistance of Conductor A be R and resistance of Conductor B be R'
Since, the material is same resistivity (ρ) is same.
Also, it is given that length is same.
R/R'=(ρl/A)/ρl/A'
R/R'=1/A/1/A'
R/R'=A'/A=1/6
R/R'=1/6
H/H'=(V²/Rt)/V²/R't
H/H'=6/1
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