Two wires a and b of the same material have their lengths in the ratio of 1:2 and their diameter in the ratio of 2:1. If they are stretched with the same force, the ratio of the increase in the length of a to that of b will be
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l = FL/AY
La/Lb = 1/2
Ia/Ib = La/πa^2 × πrb^2/Lb = 2/1
1/2×(1/2)^2 = 1/8
La/Lb = 1/2
Ia/Ib = La/πa^2 × πrb^2/Lb = 2/1
1/2×(1/2)^2 = 1/8
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